If it's not what You are looking for type in the equation solver your own equation and let us solve it.
19x^2-3x=40
We move all terms to the left:
19x^2-3x-(40)=0
a = 19; b = -3; c = -40;
Δ = b2-4ac
Δ = -32-4·19·(-40)
Δ = 3049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{3049}}{2*19}=\frac{3-\sqrt{3049}}{38} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{3049}}{2*19}=\frac{3+\sqrt{3049}}{38} $
| -3(-5n+8)=3(8n-5) | | 7/2x+.5=3x+11/2+21/3x | | 4x+7x=-27 | | -8a+3a=32 | | -3(-5n+8)=3(8n-5 | | 3x^2+15x`=18 | | -4(-7x+3)=4(1+6x) | | 24=2(j−60) | | 17+3f=17 | | 3x-2x=25-13 | | 7-1/3x=21 | | 134=2d | | 4(4+3m)=4(1m+8) | | x-7=-10x+53 | | 2h-8=-4 | | 15z-11z+3z+3=17 | | -34-3x=2(10-10x)-3 | | 4(1+2a)-10=10a-14 | | 3m-4=-1 | | 2n+3n-13n=8 | | -8n+16=-4n-5(1n-4) | | 76=2d−58 | | 76=2(d−58) | | -8(1+2p)=-41-5p | | -5(9-1n)=-37+n | | 95=5(u−75) | | 13p^2-15=-17 | | -25+8x=-3(-9x+2) | | 8+-4z=20 | | 8(c+11)=96 | | 8(r+3)=40 | | 2-2n=1n-4 |